1.A. The base lengths of the trapezoid are 35cm and 19cm. The height is 15cm. 1.B. The formula for the area of a trapezoid is A=(b1+b2)/2*h plug in the data we know A=(35+19)/2*15 A=54/2*15 A=27*15 A=405cm² since there are two trapezoids, we double that number 405*2=810cm² Answer=810cm²
1.C. To solve for this, we need to find the perimeter of the trapezoid P=35+19+17+17=88cm Answer=No. The edges of the trapezoid are longer than 80cm.
2.A. 3units. Since their x values are the same, you just subtract the y values to calculate distance 5-2=3 Answer=3
2.B A right triangle. Since one coordinate is directly above, and the other is directly to the right of the bench
3.A The two triangles would be... A=1/2b*h=1/2*30*72=15*72=1080ft² each and the center rectangle would be A=l*w=20*72=1440ft² Add them all together and you get Total area=3600ft²
