A picture frame has a perimeter of 40 inches. Its length is 2 inches greater than one-half its width. Let w represent the width of the picture frame, and let l represent the length. Which system of equations can be used to find the dimensions of the picture frame?
SOLVING (if needed) Substitute 2 + .5w in for l in the second equation and solve for w. 2(2 + .5w) + 2w = 40 4 + w + 2w = 40 Combine like terms and subtract 4 from both sides 3w = 36 Divide both sides by 3 w = 12 in. l = 2 + .5w l = 2 + .5(12) l = 8 in.
